Address
16 Nortonville Drive, Toronto, ON
Price
$ 3,500
Property Attributes
  • ID#E13629700
  • TypeSingle Family
  • Listing Status Active
  • MunicipalityToronto
  • CityToronto
  • NeighbourhoodTam O'Shanter-Sullivan
  • Postal CodeM1T 2G8
  • StyleSingle Family Dwelling
  • Price$ 3,500
  • Bedrooms4
  • Bathrooms2
  • Half Bathrooms0
  • Sqr Footage2000
Data Source:
RLP - CREA EN
Property Description

Two units in a same house with separate entrance, 2 kitchens, shared laundry. Renovated upper unit has 3 bedroom, 1 washroom. Lower unit has 1 bedroom and 1 washroom, own kitchen, walkout to the backyard. (landlord uses garage for storage, landlord does not live on site). Great for large family with in-laws, live under the same roof but separate unit. Recently Renovated, prime Scarborough Neighbourhood. Use Of 2 Parking Spot On The Driveway. Tenant Is Responsible For all Utility (Water, Gas, Garbage Removal, Electricity, hot water heater rental). Conveniently Located, Close To Ttc, Supermarket, School, Church. Minutes To Hwy401, 404, Dvp, Fairview Mall.

General Features

Terms LEASE
Neighbourhood Tam O'Shanter-Sullivan
Construction Style Semi-detached
Property Sub Type Single Family
jumpId 28866721
Property Subtype French Single Family Dwelling
Listing Type French House
MLS E13629700
Architectural Style Raised bungalow
Building Type House
Property Type Single Family
Sewer Sanitary sewer

Interior Features

Living Area Range 2000 sqft
Bedrooms 4
Basement Type None
Cooling Type Central air conditioning
Foundation Type Concrete
Heating Fuel Natural gas
Heating Type Forced air
Beds 4
Total Baths 2
Total Baths 2

Exterior Features

Exterior Finish Brick
Parking Type Attached garage, No Garage

Amenities

  • Views
  • New Construction
  • Adult 55+
  • Lease To Own
  • No Strata Fees
  • Furnished
  • Primary On Main
  • Air Conditioning
  • Seller Finance
  • Green
  • Fixer Upper
  • Horse
  • Golf
  • Fireplace
  • Deck
  • Garage
  • Basement
  • Pool

Property vs Single Family Average in M1T 2G8

Price
AVG $K
$K